Insert 2 triangles into the WPS Writer or Presentation document and drag them to meet along one of their sides. Screenshot the page to merge them together. Next, insert a circle and flatten it into a thin oval shape. Drag this thin oval shape to cover the intersection of the triangles. Use dotted lines to represent hidden-from-view lengths such as the base radius and the perpendicular heights of the compound solid. Take a screenshot of the page to merge the components into a single inseparable diagram. Use Photo Wonder or similar apps to insert text into the diagram.
Sunday, January 20, 2019
Drawing compound shapes with WPS Office : Cone + cylinder.
Insert a triangle and a cylinder into the Office document. Send the triangle to the back of the cylinder after dragging the two shapes to meet along one of their edges. Stretch the triangle to the right size. Use dotted lines to represent hidden-from-view lengths such as the base radius and the perpendicular heights of the compound solid. Take a screenshot of the page to merge the components into a single inseparable diagram. Use Photo Wonder or similar apps to insert text into the diagram.
Wednesday, January 16, 2019
How to draw a cone with WPS Office on your smartphone
Insert a triangle into the WPS Writer or Presentation document. Next, insert a circle and flatten it into a thin oval shape. Drag this thin oval shape to cover the base of the triangle. Use dotted lines to represent hidden-from-view lengths such as the base radius and the perpendicular height of the cone. Take a screenshot of the page to merge the components into a single inseparable diagram. Use Photo Wonder or similar apps to insert text into the diagram.
Thursday, May 17, 2018
Word problem
The total value of the currency notes is ₦530. How many ₦50 notes are
in the box?
SOLUTION
Let the number of ₦50 notes be x and the number of ₦20 notes be y.
Number of notes = x + y = 13................(1).
Total value of the notes = 50x + 20y = 530................(2).
Multiply (1) by 20.
20x + 20y = 260................(3).
Subtract equation (3) from (2).
30x = 270.
X = 9.
Therefore,
9 + y = 13 ................(1).
Y= 13 - 9 = 4.
Hence, there are 9 ₦50 notes (and 4 ₦20 notes) in the box.
................................................
CHECK: 9 + 4 = 13, and (50 x 9) + (20 x 4) = 450 + 80 = 530.
How to convert recurring decimals to common fractions
This requires a special process. Let the recurring decimal be equal to
a letter of the alphabet. Multiply both sides by 10 raised to power n,
where n is the number of recurring digits in the recurring decimal.
Subtract the first equation from the second and you will get the
fractional value of the recurring decimal.
EXAMPLES
(a) 0.111................
Solution.
R = 0.11... .............(1).
10R = 1.11... ................(2).
Subtract equation (1) from (2).
9R = 1.
R = 1/9.
(b) 0.1515................
Solution
X = 0.1515... .............(1).
100X = 15.1515... .............(2).
Subtract (1) from (2).
99X = 15.
X = 15/99 = 5/33.
(c)0.285714285714................
Solution
t = 0.285714... .............(1).
1 000 000 t = 285 714. 285714... .............(2).
Subtract (1) from (2).
999 999 t = 285 714.
t = 285 714 / 999 999 = 2/7.
Saturday, July 8, 2017
How to draw Maths diagrams with WPS office.
with WPS Office on your Android smartphone . Download Photo Wonder and
the latest version of WPS office (which has "Sharing by Screenshots"
on its Writer) from Google Play. Then follow the steps in the picture
below ( which was created using the same procedure I am about to teach
you).
Monday, June 19, 2017
Solution to a tricky NECO SSCE 2017 question on Variation
directly as x and the other inversely with x. When x = 2, y=4 and when
x = 5 , y = 7. Find the relationship between x and y.
Solution.
Let the two quantities be a and b.
Then,
y= k (a + b ) ...........................................(1).
a= mx .......................................................(2)
b = n/x ......................................................(3).
K, m and n are the constants of variation. Using the same letter for
the 3 constants lead to a deadlock.
Substitute Equations 2 and 3 into Equation 1.
y = kmx + (kn /x) ..................................(4).
x =2 when y= 4 turns equation 4 into:
4 = 2mk + (kn/2).
8 = 4mk + kn ...................................(5).
x=5 when y =7 turns equation 4 into :
7 = 5mk + (kn /5).
35 = 25mk + kn .............................(6).
Solve equations 5 and 6 simultaneously.
km = 9/7 and kn = 20/7.
Hence, equation 4 becomes :
y = (9/7)x + [ (20/7) ÷ x ]
= (9x/7) + (20/7x)
= (9x² + 20)/(7x).
This is the required relationship.
Confirm that y =4 when x =2 and y =7 when x =5 by substituting 2 for x
and later 5 for x in the derived relationship.
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